Mathematica Stack Exchange is a question and answer site for users of Mathematica. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

Mentioned this already in an answer to a related question. DateListPlot in Mathematica 10 has a horrible bug: If two points have the same time coordinate, only one is plotted; the others are ignored. This is different in Mathematica 9, where all points are plotted correctly. Wolfram tells me that they have this bug in their list to be fixed in the next update. For now I made a workaround with a function that makes identical time coordinates differ by a few seconds, so that DateListPlot plots all points. Has anybody another solution?

share|improve this question
This bug is now fixed in the just released version Mathematica 10.0.1 – hippo3773 Sep 30 '14 at 7:52

Here's my current workaround. Works only if the distinct time coordinates are sufficiently separated.

corr[z_] := 
  Module[{z1, z2},
    z1 = SplitBy[SortBy[z, First], #[[1]] &];
    z2 =
        Transpose[{z1[[k, All, 1]] + Range[0, Length[z1[[k]]] - 1], z1[[k, All, 2]]}], 
        {k, Length[z1]}];
    Partition[Flatten[z2], 2]]

and DateListPlot on a two column array z is then called as

DateListPlot[corr[z], ...]
share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.