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ttt = 
  Table[(z /. FindRoot[eqn1[x, z, y], {z, z0}]), 
    {x, 2.5*10^9, 3.5*10^9, 10^8/5}, 
    {y, 0.6 10^-15, 1.4 10^-15, 10^-16}, 
    {z0, 0.100, 0.110, 0.005} ];

MatrixForm[ttttt = Map[Max[#] - Min[#] &, ttt, {2}]];

ListPlot[Transpose[ttttt], Joined -> True, PlotMarkers -> Automatic, PlotRange -> All];

I know what FindRoot does, it finds the roots of z of eqn1[x, z, y] == 0, and z0 is the initial value where FindRoot searches for a root.

So the first expression simply finds roots of z about 0.1, 0.11, 0.005 while iterating x and y.

I'm puzzled by the second expression, the one involving Map[Max[#] - Min[#] &, ttt, {2}]. I think it searches for the maximum and subtracts the minimum? Does it pick from a single root near one value of z0 or for all three simultaneously?

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closed as off-topic by Yves Klett, Öskå, Michael E2, Mr.Wizard Jul 25 '14 at 17:38

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Map shows that {2} applies functions to the elements at level 2, in your case a triplet of z values for a given value of x and y. –  Timothy Wofford Jul 25 '14 at 16:40
This question appears to be off-topic because it is too localized und not useful for future visitors. –  Yves Klett Jul 25 '14 at 17:05

1 Answer 1

ttt will be a 51 x 9 matrix of triplets, the roots of eqn1 found near to the three values of z0 for the 51 values of x and the 9 values of y. Map[Max[#] - Min[#] &, ttt, {2}]] works at level 2, the level of the triplets. It finds the span of those roots; i.e., Max @ {root1, root2, root3} - Min @ {root1, root2, root3}, and returns a 51 x 9 matrix of those span values.

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