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I have a CSV file with $9$ columns. I want to plot them in the following way. Column $1$ will be along the $X$-axis. Any point $(x_i, y_i)$ of $i$-th curve in the plot will have the $x$ value from the corresponding row of column $1$ and the $y$ value from the $x$-th row of the $(i-1)$-th column. So, there will be $8$ curves in the plot. The file could be downloaded from this link. The code is:

data = Import["iso-pair-data.csv", "CSV"]; ListPlot[{data[[All, 2]],
data[[All, 3]], data[[All, 4]]}, Joined -> True, PlotMarkers -> Automatic]

I am not getting the plot as expected. Any help?

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I think this is what you're trying to do: ListPlot[Rest@Transpose@data, Joined -> True, PlotRange -> Full] –  Pickett Jul 16 at 20:40
I do not get it. Lets say i=2, ok? So the first column is the x-values, fine. Now the y-values you are saying come from the rows of the (i-1) column? but this is 1 in this case? But that is supposed to be the x-values for all the other columns. Are you simply trying to plot columns 2-9 against the first column? –  Nasser Jul 16 at 20:40
@Nasser It should be i+1... if you use all the information in the question I don't think there can be any doubt. –  Pickett Jul 16 at 20:43

1 Answer 1

up vote 4 down vote accepted

Does this work for you?

vals = Table[Transpose[{data[[All, 1]], data[[All, i]]}], {i, 2, 
ListLinePlot[vals, Joined -> True, 
 PlotRange -> {Automatic, {0, Max[data[[All, 2 ;;]]]}}, 
 ImageSize -> Large]

enter image description here

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