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How does one set a logarithmic scale for both x and y axes in ContourPlot in Mathematica?

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up vote 35 down vote accepted

One possibility is to plot the contour plot with linear scales using ContourPlot and use ListLogLogPlot to transform this plot to one with logarithmic scales:

pl = Normal@
   Sin[3 x] + Cos[3 y] == 1/2, {x, .01 Pi, 3 Pi}, {y, .01 Pi, 3 Pi}, 
   PlotPoints -> 30]

Mathematica graphics

ListLogLogPlot[Cases[pl, Line[a_, b___] :> a, Infinity], 
 Joined -> True, Frame -> True, PlotRange -> All, AspectRatio -> 1, 
 PlotStyle -> ColorData[1][1]]

Mathematica graphics

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I keep missing the fun questions. Nice answer. +1 – Mr.Wizard May 7 '12 at 8:56
Great idea! I never thought of that. – sebhofer May 7 '12 at 15:15
One disadvantage this method might have is that of point sampling. The right hand and the upper parts are better sampled than the left hand and lower parts of the plot. This might lead to curves that are less smooth on one side than on the other. – Sjoerd C. de Vries May 7 '12 at 17:33

As a slight variation of the nice suggestion above add FrameTicks to get the tick labels you want.

 Sin[3 Exp[x]] + Cos[3 Exp[y]] == 1/2, {x, Log[0.01 Pi], 
  Log[3 Pi]}, {y, Log[0.01 Pi], Log[3 Pi]}, PlotPoints -> 30, 
 FrameTicks -> {Table[{y, ToString[Round[10^y, 0.001]]}, {y, 
     Log[10, 0.001], Log[10, 100]}], 
   Table[{y, ToString[Round[10^y, 0.001]]}, {y, Log[10, 0.001], 
     Log[10, 100]}]}]
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Your example uses a base-E log scale for the plotting and a base-10 log scale for the ticks. Shouldn't these be consistent? – Sean Madsen Nov 16 '13 at 4:16

Instead of doing some transformation on the original ContourPlot we can do an exponential rescaling of the original variables in the ContourPlot, so this is somewhat different approach to get roughly the same result :

ContourPlot[ Sin[ 3 Exp@x] + Cos[ 3 Exp@y ] == 1/2, 
             {x, Log[0.01 Pi], Log[3 Pi]}, {y, Log[0.01 Pi], Log[3 Pi]}, PlotPoints -> 30]

enter image description here

The only difference is a different coordinate system.

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