Take the 2-minute tour ×
Mathematica Stack Exchange is a question and answer site for users of Mathematica. It's 100% free, no registration required.

I have a nested matrix n:

n = {{a, b}, {c, d}}
a = {{0, t, q, dh}, {0, 1, 0, th}, {1, 0, 0, sh}}
b = {{0, t, q, dh}, {0, 0, 0, th}, {0, 0, 1, sh}}

c = {{0, t, q, dh}, {1, 0, 1, th}, {0, 0, 0, sh}}
d = {{0, t, q, dh}, {0, 1, 0, th}, {1, 0, 0, sh}}

With thanks to Kuba and Mr.Wizard 'comparison-operation-for-nested-matrices' I could get a combined nested matrix: ncombined (on which a comparison operation was applied)

ncombined= {{
   {{0, t, q, dh}, 
    {0, 1, 0, th}, 
    {1, 0, 1, sh}}},
   {{{0, t, q, dh}, 
    {1, 1, 1, th}, 
    {1, 0, 0, sh}}
           }}

and with thanks to Kgular getting-good-looking-matrix..I could add a vector m as:

m = {rr, kk}

to the ncombined as bellow:

pp = Transpose[Insert[Transpose[ncombined], Flatten@m, 1]];
ppgoodlook=MapAt[MatrixForm, pp, {{All, All}, {}}]

enter image description here

I am so sorry if my question maybe will not well written while I have so much tried to write it more obviously. Also I will bring the image of the desired result.

question: Since, number 1 is not repeated in the same elements of a and b , also for c and d, how can I refer each of 1 in the ppgoodlook to the main sub_matrices such as a, b, c or d (from which, 1 is gone to ppgoodlook) in order to obtain the bellow result (However this referring is regardless to the letters of sub_matrices such as sh,th, q, t and dh) :

enter image description here

share|improve this question

1 Answer 1

ncombined = {{{{0, t, q, dh}, {0, 1, 0, th}, {1, 0, 1, sh}}},
              {{{0, t, q, dh}, {1, 1, 1, th}, {1, 0, 0, sh}}}};
pos = Join @@ (Thread[{Position[#1, 1], #2}] & @@@ 
     Thread[{{a, b, c, d}, {"a", "b", "c", "d"}}]);
pos = pos /. {{{x_, y_}, p : "a" | "b"} :> {{1, 1, x, y},  p}, 
              {{x_, y_}, p : "c" | "d"} :> {{2, 1, x, y}, p}};
ncombined2 = ncombined;
(ncombined2[[Sequence @@ #[[1]]]] = #[[2]]) & /@ pos;
m = {rr, kk};
pp2 = Transpose[Insert[Transpose[ncombined2], Flatten@m, 1]];
ppgoodlook2 = MapAt[MatrixForm, pp2, {{All, All}, {}}]

enter image description here

share|improve this answer
    
Thanks a bunch for your answer, Should you extend your answer to a general problem. I mean if we do not know the exact palace of 'a' and 'b' also, 'c' and 'd'. you separated, a and b, c and d in the line: pos = pos /. {{{x_, y_}, p : "a" | "b"} :> {{1, 1, x, y}, p}, {{x_, y_}, p : "c" | "d"} :> {{2, 1, x, y}, p}}; But if we have d in the topmost sub_matrices near the a and b, what must we do? –  mostafa Jul 1 at 14:00

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.