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How could I expand this equation (0.837 + x^0.5 + x)^4.870


Expand[(0.837 + x^0.5 + x)^4.870]


Series[(0.837 + x^0.5 + x)^4.870, {x, 0, 6}]


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You can do Series[(0.837 + x^(1/2) + x)^4.870 , {x, 0, 6}] i.e. switch x^0.5 to x^(1/2) or simply Series[(0.837 + x^0.5 + x)^4.870 // Rationalize, {x, 0, 6}] – Artes Apr 27 '14 at 16:09
Usually an equation has an equal sign.. – Daniel Lichtblau Apr 28 '14 at 21:55

1 Answer 1

It very strongly depends upon the answer to the question, why do you want to make the expansion and what is the range of x? For this reason in addition to the answer of Artes in the comment above you might think of the following approach for 0<x<1. This makes a fit of your function to a cubic polynomial:

    lst = Table[{x, (0.837 + x^0.5 + x)^4.870}, {x, 0, 1, 0.01}];
ft = Fit[lst, {x, x^2, x^3}, x];
  ListPlot[lst, PlotStyle -> Blue],
  Plot[ft, {x, 0, 1}, PlotStyle -> Red]

That is how the fit looks like: enter image description here The blue points is your function and the red line is the fit. If this is a satisfactory coincidence, your expansion (or better to say, your approximation) is:


(*  26.173 x + 20.6356 x^2 + 113.437 x^3  *)
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