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I'm trying to solve simple parametric equations using mathematica, but I'm having trouble finding a function to do this... what is the simplest way to solve for a common variable?

For example, I have y=t x=t, and I want to solve for y=x.

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closed as off-topic by Michael E2, belisarius, Sjoerd C. de Vries, Yves Klett, Oleksandr R. Mar 3 at 7:33

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – Michael E2, Sjoerd C. de Vries, Yves Klett, Oleksandr R.
If this question can be reworded to fit the rules in the help center, please edit the question.

1  
There's Eliminate, Reduce and Solve. –  Michael E2 Mar 3 at 5:35
2  
Perhaps you could elaborate/clarify. Does the suggested edit by olliepower correspond to your use case? And how about his answer? –  Jacob Akkerboom Mar 3 at 9:33
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Yup, my thoughts exactly. The edit changes the original use case somewhat. –  Ajasja Mar 3 at 9:42
    
@MichaelE2 My edit changes the original case a little bit, but I think it turns a boring question into a much more interesting one. IE, how do we convert from polar coordinates (defined only by the parameter theta if we keep rbar constant), to cartesian coordinates. Also, i'm personally interested in that question :) –  olliepower Mar 4 at 6:05
    
@olliepower It appears your edit was not approved, perhaps because it was thought to be a new question. You could ask your question separately, although I would think the standard conversion rules would work in your case. Have to wait and see what the question is, I guess. :) –  Michael E2 Mar 4 at 12:49

1 Answer 1

up vote 1 down vote accepted
Eliminate[{y == t, x == t}, t]

gives

y == x
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