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I have a list with some values and I want to replace a value which is greater than 1 with 1 otherwise keep the value. In this case 10562:

   list[[1]]= {0.61975, 10562., 0.43274, 0.15068, 0.13703, 0.057564}

I tried this approach:

Table[If[list[[1, x]] > 1, list[[1, x]] = 1, list[[1, x]]], {x,
   1, Length[list[[1]]]}]

It works, but I'm wondering if there is a much simpler solution with mathematica. Can anybody help me out?

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possible duplicate of Replacing all values in a table > $T$ + changeing specific values. –  Kuba Jan 31 at 21:46
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marked as duplicate by Mr.Wizard Feb 2 at 7:41

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2 Answers

up vote 9 down vote accepted

Use Clip:

Clip[{0.61975, 10562., 0.43274, 0.15068, 0.13703, 0.057564}, {-Infinity, 1}]

{0.61975, 1, 0.43274, 0.15068, 0.13703, 0.057564}

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Thank you, much easier :) –  holistic Jan 31 at 15:09
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{0.61975, 10562., 0.43274, 0.15068, 0.13703, 0.057564} /.x_ /; x >= 1 -> 1
(*  {0.61975, 1, 0.43274, 0.15068, 0.13703, 0.057564}  *)
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There's definitely more than one way to do it in Mathematica. :-| –  kirma Jan 31 at 15:46
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@kirma Clip will perform much better than this replacement rule; you chose the best one I know of. –  Mr.Wizard Jan 31 at 15:48
    
@krima Clip is, of course, better, since it is a function specially designed for purposes of such a sort. I believe, however, that it is useful to have several solutions, even if they are not as good. Further, what is better and what is worse depends upon the point of view. People usually think that the good==fast. However, we often deal with problems in which the timing of application one approach imperceptibly differs from another. –  Alexei Boulbitch Feb 3 at 8:54
    
@krima, continuation: In this case the best solution is the first coming to mind, provided it gives an answer in the matter of a second, since in this case it is the looking for solution that is the time-limiting step. Anyway, I like your solution more than mine. –  Alexei Boulbitch Feb 3 at 8:55
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