# How can we tell Series to treat the expansion parameter as an integer?

It is simple for Mathematica to find an asymptotic expansion for $\frac{1}{-1+p}$ as $p \rightarrow \infty$. However, if we want to restrict $p$ to be an integer and also include some terms that simplify for integer p (but not generally) then Series by itself will no longer do the job (without some prodding, I expect).

Is there a simple way to use Series to find the asymptotic expansion of $$\frac{1}{(-1)^p+p}$$ as $p \rightarrow \infty$, assuming integer $p$?

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Simplicity is arguably in the eye of the beholder, but the following code gets you closer to $\sum_{k=0}^{n}(-1)^k p^{-(k+1)}$
ps = Series[1/((-1)^p + p), {p, \[Infinity], 1}];