Take the 2-minute tour ×
Mathematica Stack Exchange is a question and answer site for users of Mathematica. It's 100% free, no registration required.

As per the answer to this question: SolveAlways rejects inequality, I tried the following commands:

Clear[f, x]
D[Erf[x  f[x]], x]
Reduce[D[Erf[x  f[x]], x] <= 0, Reals]

Which gives the following output:

(2 E^(-x^2 f[x]^2) (f[x] + x f'[x]))/Sqrt[[Pi]]

Reduce::nsmet: This system cannot be solved with the methods available to Reduce. >>

I would like to use the relation D[Erf[x f[x]], x] <= 0 to find a relation between f[x] and f'[x] over the domain x >= 0.

I know that x is positive and real, and that f[x] is a function from Reals to Reals, and that it is positive, continuous, and differentiable, but the exact form of the function is unknown.

In this case, it is clear that the derivative will be less than or equal to zero whenever f[x] <= -x f'[x] but I can't get Mathematica to work with me.

Any ideas on how I can use Mathematica to find the relation f[x] <= -x f'[x]?

share|improve this question

1 Answer 1

Since the term Sqrt[Pi] in the denominator is a positive constant, the equation is negative exactly when the numerator is negative. Hence

Numerator[D[Erf[x f[x]], x]] <= 0

which gives

enter image description here

This is the same as the inequality you are looking for.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.