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I want to export the data of a three dimensional histogram in the format

#   x     y     z  

with a blank line between different lines, so that one can plot the histogram in gnuplot simply using

splot 'data.dat' u 1:2:3 w l

What is the right way to obtain that?

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Can you use this?… – C. E. Dec 4 '13 at 17:06
You could add some code to generate the data you refer to. It should be a fairly trivial task for Export - did you already try something along this line? – Yves Klett Dec 4 '13 at 17:19
up vote 2 down vote accepted

this is how you get your data..

example = 
   Transpose@{RandomVariate[NormalDistribution[0, 1], 1000], 
              RandomVariate[NormalDistribution[0, 2], 1000]};
list = HistogramList[example];
x = list[[1, 1]];
y = list[[1, 2]];
data = Flatten[
      MapIndexed[ {x[[#2[[1]]]], y[[#2[[2]]]], #1} &, list[[2]] , {2}], 1];

now exporting to a gnuplot form..

Export["test.txt", data // N, "Table"]

I dont have gnuplot on this machine to test but it should be close

Edit.. generalization to higher dimensions:

dim = TensorRank[Last@list];
data = Flatten[MapIndexed[ 
         Append[Table[(First@list)[[k, #2[[k]]]], {k, dim}], #1] &, 
         Last@list ,{dim}], dim - 1];

Adding blanks, and a header comment:

      Prepend[Riffle[N@data, "  ", 
              1 + Last@Dimensions@Last@list], {"# x y z"}], "Table"]
share|improve this answer
yes, there is only the further need of a blank line between different blocks – psmith Dec 4 '13 at 17:31
it doesn't work, it puts the blank line in the wrong place. – psmith Dec 4 '13 at 18:14
Ok, Fixed that.. the automatic dimensions are not square and I used the wrong dimension in Riffle. – george2079 Dec 4 '13 at 18:59
0k perfect, thanks – psmith Dec 4 '13 at 19:01

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