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I can't seem to solve the general quadratic equation:

 Solve[ax^2 + bx + c == 0, x]

 Out[299]= {}

It just outputs the empty list. How do I solve this equation?

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closed as off-topic by m_goldberg, Artes, rm -rf Oct 21 '13 at 3:55

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1 Answer 1

up vote 4 down vote accepted

Firstly,you must know bx is different from b x,because bx is only a varible while b x are two varibles.

Solve[a x^2 + b x + c == 0, x]

{{x -> (-b - Sqrt[b^2 - 4 a c])/( 2 a)}, {x -> (-b + Sqrt[b^2 - 4 a c])/(2 a)}}

Attention the blank space between a and x^2.Good luck!

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@Tyler Durden,when a constant times a varible,you could not left a blank space between them or use * to replace Times. –  Tangshutao Oct 20 '13 at 9:22
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