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Is there a straightforward way to go from an ordered list like:

ord = {a, b, c, d, e, f, g, h}

to a disordered list like:

randompos = {c, h, d, g, a, b, f, e}

I can use something like:

DeleteDuplicates @ RandomChoice[ord, 50]

but it's not really robust. Is there an easier way?

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3  
Use RandomSample. –  Spawn1701D Jun 25 '13 at 3:44
1  
@Spawn1701D RandomSample won't be able to create the letter i out of thin air. The OP needs a god –  belisarius Jun 25 '13 at 3:46
1  
@Spawn1701D That is a simplistic way :) –  belisarius Jun 25 '13 at 3:48
1  
@belisarius typo fixed. i have no need for the divine. –  geordie Jun 25 '13 at 4:09
1  
RandomSample[#,Length[#]]&@ord –  HyperGroups Jun 25 '13 at 4:13
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1 Answer

up vote 4 down vote accepted

Method1 RandomSample


as @Spawn1701D and @Oleksandr R.said in comment,

RandomSample[ord] is sufficient.

ord = {a, b, c, d, e, f, g, h};

RandomSample[ord]

(*
    {c,e,g,b,h,f,a,d}
*)

To get one sublist

RandomSample[#, Length[#] - 4] & @ ord

(*
    {g,h,e,f}
*)

Method2 RandomPermutation


SeedRandom[1234]; Permute[ord, RandomPermutation[8]]

(*
    {b,f,e,h,d,g,c,a}
*)

One aside: sometimes when people's comments are apparently feasible to the question, they might not likely to answer the post, others may wish the first people who leave the good comment to answer the question, and OP is also encouraged to answer its own question.

So I answer the little post with one additional method.

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1  
@HyperGoups -- no need to apologize. If the commenter wanted to answer, he would have spawned one by now. –  bill s Jun 26 '13 at 5:21
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