Take the 2-minute tour ×
Mathematica Stack Exchange is a question and answer site for users of Mathematica. It's 100% free, no registration required.

First of all, I would like to apologize in advance if I don't use the correct terms or if I express myself unclear but I just started to work with Mathematica.

I'm simulating electricity prices and therefore created a table which show 10 possible price movements (the rows) over the next 10 days (the columns).

But as I'm only interested in the prices if they once moved over a limit of 1.2 I used the function LengthWhile and then Take and got the following output:

{{1.14213, 1.22155, 1.23436, 1.35038, 1.35104, 1.48351}, {1.0484, 
  1.42157, 1.57688, 2.07304, 1.61537, 1.326, 1.18823, 1.4154, 1.56133,
   1.93402}, {1.06792}, {1.19792, 1.77863, 2.24724, 2.27939, 2.15542, 
  2.47559}, {1, 1.31003, 1.06341, 1.17975, 0.966335, 0.90843, 0.70606,
   0.683366, 0.762621, 0.716291, 
  0.631823}, {0.428993}, {0.636747}, {1, 1.35605, 1.06939, 1.09904, 
  1.14575, 1.05545, 1.13386, 0.868574, 0.846754, 0.702533, 
  0.864972}, {1.08078, 1.29863, 1.17577, 0.995288, 
  1.05625}, {0.637442}}

If I use ListLinePlot now, all lines are starting at 1 on the x-axis and then ending on different points. But I want them all to end at 10 on the x-axis and therefore starting at different points on the x-axis. Can anybody help me here?

Thanks!

share|improve this question
add comment

1 Answer

up vote 2 down vote accepted

Is this what you want?

ls={{1.14213, 1.22155, 1.23436, 1.35038, 1.35104, 1.48351}, {1.0484, 1.42157, 1.57688, 2.07304, 1.61537, 1.326, 1.18823, 1.4154, 1.56133, 1.93402}, {1.06792}, {1.19792, 1.77863, 2.24724, 2.27939, 2.15542, 2.47559}, {1, 1.31003, 1.06341, 1.17975, 0.966335, 0.90843, 0.70606, 0.683366, 0.762621, 0.716291, 0.631823}, {0.428993}, {0.636747}, {1, 1.35605, 1.06939, 1.09904, 1.14575, 1.05545, 1.13386, 0.868574, 0.846754, 0.702533, 0.864972}, {1.08078, 1.29863, 1.17577, 0.995288, 1.05625}, {0.637442}};

ListPlot[PadLeft[#, 10, None] & /@ ls,Joined->True]

enter image description here

share|improve this answer
    
Yes, thank you! –  mary Apr 19 '13 at 15:41
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.