# Strange result from evaluating a Limit expression

When I evaluate the limit of (1-Cos[x]) Sin[1/x] at x = 0 in Mathematica 9, I obtained Interval[{-2, 2}]. The problem is that this limit is 0. It is also 0 when I compute it by Maple and Mathematica 7. So, I wonder whether I've found a bug in Mathematica 9?

Limit[(1 - Cos[x]) Sin[1/x], x -> 0]

Interval[{2, 2}]

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Are you sure that you didn't write by mistake (1+Cos[x]) Sin[1/x]? –  Spawn1701D Apr 11 '13 at 1:45
What subversion of 9 you have? Did you run the command after a initializing the kernel? If this is true its a big mess up! It's like saying that $\cos(0)=-1$! –  Spawn1701D Apr 11 '13 at 2:04