This question is similar to a previous question, but I did not find an adequate answer there.
If I type in the command
BodePlot[1/(s^2)] I get a horizontal line at +180° for the phase plot. Based on the books Linear Control System Analysis & Design, 3rd Ed by D'Azzo and Houpis (pg. 259) and Feedback Control of Dynamic Systems by Franklin and Powell, 3rd Ed (pg 348), as well as MATLAB, the phase should be -180°. This particular problem is about as basic as it gets.
BodePlot[1/(s^4)], Mathematica gives +90° and 0°, instead of the conventional -270° and -360°.
I believe this all stems from the way Mathematica calculates the phase of a complex number. If I type
Arg[1/(I^4)], I get $\pi$, $\pi/2$ and $0$, respectively.
So, my question is, how do I get
BodePlot to follow the convention I would like to follow? I do not see an option under the
BodePlot documentation to make this happen.