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I want to subtitute $x = 1$ into the expression $$f(x)=x^2 + 3 (x^2 - m^2) + \sqrt{x^2 + 1}$$ but I don't calculate the value $f(1)$, that is mean, I want $$1^2 + 3(1^2-m^2)+\sqrt{1^2 + 1}.$$ If I tried

f[x_] := x^2 + 3 (x^2 - m^2) + Sqrt[x^2 + 1];
f[1]

I receive

1 + Sqrt[2] + 3 (1 - m^2)

How do I tell Mathematica to do that?

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Dirty trick : f["1"]. –  b.gatessucks Feb 26 '13 at 8:21
    
Thank you very much. –  minthao_2011 Feb 26 '13 at 8:22
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1 Answer 1

up vote 8 down vote accepted
  f[x_] := x^2 + 3 (x^2 - m^2) + Sqrt[x^2 + 1];


  f[HoldForm@1]   (* thanks: @chris *)

or

  f[Defer@1] 

enter image description here

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1  
what's wrong with f[Defer[x]] /. x -> 1 ? The order? –  chris Feb 26 '13 at 8:38
    
@chris, right!!! thanks –  kguler Feb 26 '13 at 8:42
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