I'm trying to use Mathematica to evaluate many values of $f(x,y) $, like $f(-\pi,\pi) $ for
$$f(x,y) = \left( \frac{-1}{4}\sin \left( \frac{x-y}{2} \right)\sin y \right)\left( \frac{-5}{4}\sin \left( \frac{x-y}{2} \right)\sin y-\cos \left( \frac{x-y}{2} \right)\cos y \right) \\-\frac{1}{4}\left( \sin \left( \frac{x-y}{2} \right)\sin y+\cos \left( \frac{x-y}{2} \right)\cos y \right).$$
So I input :
f[x_, y_] := ((-1/4) sin[(x - y/2)] sin[y])
((5/4) sin[(x - y/2)] sin[y] - (-1/4) cos[(x - y/2)] cos[y])
- (1/4) (sin[(x - y/2)] sin[y] + cos[(x - y/2)] cos[y])
and
f[-\[Pi], \[Pi]]
Mathematica then outputs :
1/4 (-cos[-((3 \[Pi])/2)] cos[\[Pi]] -
sin[-((3 \[Pi])/2)] sin[\[Pi]]) -
1/4 sin[-((3 \[Pi])/
2)] sin[\[Pi]] (1/4 cos[-((3 \[Pi])/2)] cos[\[Pi]] +
5/4 sin[-((3 \[Pi])/2)] sin[\[Pi]])
But I want my final answer to be a number. Why didn't Mathematica evaluate the trigonometric functions? Thank you.

x-y/2", because it rarely equals $\frac{x-y}{2}$. – whuber Jan 9 at 0:13