Hard to do it analytically. Tried convolution theorem also. ForuierTransform had hard time with it as well as Integrate. So, here is a numerical solution.
The support needed is really only from $0$ to $2 \sqrt(2)$ since your function exist over $0$ to $\sqrt(2)$ but I integrated it over little larger range for the plot to look better.

Hence
f[t_?NumericQ] :=
Piecewise[{{t*(Pi - 4*t + t^2),
Inequality[0, Less, t, LessEqual,
1]}, {(-t)*(2 + t^2 - 4*Sqrt[-1 + t^2] - 2*ArcCsc[t] +
2*ArcTan[Sqrt[-1 + t^2]]), 1 < t < Sqrt[2]}}, 0];
g[t_?NumericQ] :=
NIntegrate[f[tao] f[t - tao], {tao, -Infinity, Infinity}]
data = Table[{t, g[t]}, {t, -0.5, 6, .01}];
Show[ListLinePlot[data, PlotStyle -> Red, PlotRange -> All],
Plot[f[t], {t, -.5, 6}, PlotRange -> All, Exclusions -> None]]

The red plot is the convolution and the blue curve is $f(t)$
NIntegrate? – b.gatessucks Jan 8 at 8:28