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1
 
In:

D[Sum[Sin[x],x],x]

D[Sum[f[x],x],x]


Out:

1/2 Cos[1/2 (-1 - Pi + 2 x)] Csc[1/2]

0

Function f is undefined, but Mathematica 9 counts it as constant?

Mathematica 8 returns

Mathematica graphics

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It's because you take derivative with respect to the local parameter of the sum. Sum itself doesn't depend on x. But in the case of Sin[x] it simplifies it first to the expression dependent of x. So it's not a bug. – swish Dec 19 '12 at 9:42
@swish so it is good if undefined function is counted as zero? – Anixx Dec 19 '12 at 9:49
Even more, the sum of a defined function and undefined one also gives zero: D[Sum[f[x] + Sin[x], x], x] -> 0 – Anixx Dec 19 '12 at 9:51
3  
@Anixx If sum can be simplified then Sum[f[x],x] is the same as Sum[f[y],{y,0,x-1}]. But without specifying the limits it's not a function, because x is an index variable not an upper limit. – swish Dec 19 '12 at 10:12
1  
@swish No matter what you expect it to mean, you will have to agree that if D[Sum[Sin[x],x],x] has a nonzero value, then D[Sum[f[x],x],x] cannot be zero in general, since we might have f==Sin. – jVincent Dec 19 '12 at 12:23
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1 Answer

up vote 2 down vote

Probably this is just a bug. Especially since it "works" in 8. You could fix it by doing 

SetOptions[D, NonConstants -> {Sum}]

first, or by putting this in your init.m file.

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1  
Sorry, but I wouldn't do that. Even in version 8 you would expect D[Sum,x] == 0 to be True, wouldn't you? – Jens Dec 19 '12 at 22:02
1  
Well, we are supposed to use lower case letters for variables. Anyway, of course this is not a real fix, just a hack as a reminder that something is fishy in 9.0.0 (waiting for 9.0.1 anyway any day, aren't you, too?) – Rolf Mertig Dec 19 '12 at 22:38
Actually, I think I'm just waiting to get version 5.2 back one day... – Jens Dec 19 '12 at 22:42
Sum[f[x],x] gave an error there ... – Rolf Mertig Dec 19 '12 at 22:47
Well, are things better now? Anyway, I'm only kidding about the good old times... they weren't that good, either, I guess. – Jens Dec 19 '12 at 22:52

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