How to get a solution involving logs in the right form?

How do I get

Solve[(1/9)^(r/2) == 1/n , r]


to give me

 Log[n]/Log[3]


and not

-Log[1/n]/Log[3]?

-
Thanks. Solve may have just been the wrong command. –  lip1 Dec 11 '12 at 15:18
@b.gatessucks Perhaps you should consider posting working answers, however short they may be, as answers and not as comments. The list of seemingly unanswered questions is growing and growing. I won't hold it against you ;-) –  Sjoerd C. de Vries Dec 11 '12 at 15:35
You can get the result with Solve, you can do e.g. this Simplify[ Solve[ (1/9)^(r/2) == 1/n, r, Reals], n > 0]. –  Artes Dec 11 '12 at 15:37
@SjoerdC.deVries the alternative is someone collects all these answers in comments and produce 200 answers ;-) –  chris Dec 11 '12 at 15:44
Or I can answer my own question with the comments :) –  lip1 Dec 11 '12 at 15:45

Reduce[(1/9)^(r/2) == 1/n && n > 0, r, Reals]