# Grid — Row expressions not evaluated [closed]

Can anyone explain why in the following Grid expression the Row expressions are not evaluated ...

Grid[{{Row[1, " a"], Row[2, " b"]}, {Row[3, " c"], Row[4, " d"]}},
Dividers -> All]


... but when I do it this way they are?

row = (Row@{##}) &;
Grid[{{row[1, " a"], row[2, " b"]}, {row[3, " c"], row[4, " d"]}},
Dividers -> All]


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The answer is hidden in your question. The construction Row@{##}& works because Row takes a vector/list of expressions as input and with the {} you have defined such a vector! Try Row[{1,"a"}] will also work similar fashion. –  PlatoManiac Oct 22 '12 at 18:39

## closed as too localized by Mr.Wizard♦Oct 22 '12 at 18:49

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Row[] takes a list as the argument.

In your first case, you failed to provide a list.

row = (Row@{##}) &;